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p^2-9p-22=0
a = 1; b = -9; c = -22;
Δ = b2-4ac
Δ = -92-4·1·(-22)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-13}{2*1}=\frac{-4}{2} =-2 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+13}{2*1}=\frac{22}{2} =11 $
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